Gf besitzt einen Wendepunkt an der Stelle x = a
⇔
f ´´ (a) = 0 und Vorzeichenwechsel von f ´´ bei x = a
\(f(x)=-2xe^x\)
Wendepunkt: \(W( ▉ \mid ▉ e^ ▉ )\)
Bestimme die 2. Ableitung:
\(\class{mathjax-input mathjax-input-0}{\mspace{3mu}\Rule{1.4em}{0.9em}{0.3em}\mspace{3mu}}-2e^x\cdot(1+x)\quad\) \(\class{mathjax-input mathjax-input-1}{\mspace{3mu}\Rule{1.4em}{0.9em}{0.3em}\mspace{3mu}}-2e^x\quad\) \(\class{mathjax-input mathjax-input-2}{\mspace{3mu}\Rule{1.4em}{0.9em}{0.3em}\mspace{3mu}}\, (-4-2x)e^x \quad\) \(\class{mathjax-input mathjax-input-3}{\mspace{3mu}\Rule{1.4em}{0.9em}{0.3em}\mspace{3mu}}\;(2-2x)e^x\)
Regeln zur Transformation von Graphen